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Let x^2-3x+p=0 has two positive roots aa...

Let `x^2-3x+p=0` has two positive roots `aa n db` , then minimum value if `(4/a+1/b)` is,

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The correct Answer is:
3

a + b = 3
H.M `ge` A.M for numbe `(a)/(2), (a)/(2)`, b. We have
`(3)/((2)/(a) + (2)/(a) + (1)/(b)) le ((a)/(2) + (a)/(2) + 6)/(3) = 1`
`:. 1 ge (3)/((2)/(a) + (2)/(a) + (1)/(b))`or `(2)/(a) + (2)/(a) + (1)/(b) ge 3`
`:. (4)/(a) + (1)/(b) ge 3`
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