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Solve (dy)/(dx)=(x-2y+5)/(2x+y-1)...

Solve `(dy)/(dx)=(x-2y+5)/(2x+y-1)`

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We have, `2xdy+ydy-dy=xdx-2ydx+5dx`
`2(xdy+ydx)+ydy-dy=xdx+5dx`
`2d(xy)+ydy-dy=xdx+5dx`
Integrating, we get
`2(xy) +y^(2)/2-y=x^(2)/2+5x+c`
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