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Solve sec^(2)x tany dx+sec^(2)y tanx dy=...

Solve `sec^(2)x tany dx+sec^(2)y tanx dy=0`

Text Solution

Verified by Experts

The correct Answer is:
`(tanx)(tany)=c`
The given equation can be rewritten as
`int(sec^(2)x)/(tanx)dx+ int(sec^(2)y)/(tany)dy=logc`
or `log tanx+log tany=logc,` where c is an arbitary positive constant.
or `tanxtany=c`.
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