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x(dy)/(dx)=y(logy-logx+1)...

`x(dy)/(dx)=y(logy-logx+1)`

A

`logx/y=cy`

B

`logy/x=cy`

C

`logy/x=cx`

D

None of these

Text Solution

Verified by Experts

The correct Answer is:
C

`(dy)/(dx)= y/x[logy/x+1]`
Put `y=vx`
`v+x(dv)/(dx) = vlogv+v`
`therefore (dv)/(vlogv) = (dx)/x`
`therefore log(logv)=logx+logc=logcx`
`therefore logy/x=cx`
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CENGAGE PUBLICATION-DIFFERENTIAL EQUATIONS-All Questions
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