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Period of f(x) = sgn([x] +[-x])is equal ...

Period of `f(x) = sgn([x] +[-x])`is equal to (where [.] denotes greatest integer function

A

1

B

2

C

3

D

does not exist

Text Solution

Verified by Experts

The correct Answer is:
A
Let `f(x)=sgn([x]+{-x])`
`={{:(0,,x in I),(-1, , x cancelinI):}`
Hence f(x) is periodic with period 1.
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