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The I.F of x((dy)/(dx))+(logx)y=x^(-1/2...

The I.F of `x((dy)/(dx))+(logx)y=x^(-1/2logx)` is

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`(dy)/(dx)+(log x)/(x) y = x^(-1/2 log x)`
I.F `= e^(int(log x)/(x)dx)=e^((log x)^(2)/(2))=(e^(log x))^((log x)/(2))=x^(1/2 log x)`
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