S CHAND IIT JEE FOUNDATION|Exercise SELF ASSESSMENT SHEET-6 |1 Videos
ALGEBRAIC EXPRESSIONS
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ALGEBRIC IDENTITIES
S CHAND IIT JEE FOUNDATION|Exercise Self Assessment Sheet-7|10 Videos
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At what point the origin be shifted so that the equation x^(2)+xy3xy+2=0 does not contain any first degree term and constant term?
Constant polynomial a polynomial consisting of a constant term olay is called a constant polynomial.the degree of a constant polynomial is zero.
If first degree terms and constant term are to be removed from the equation 12x^(2)+7xy-12y^(2)-17x-31y-7=0 , then the origin must be shifted at shifted at the point .
f(x)g(x)=0 where f(x) and g(x) are degree 2 polynomial with sum of zeroes -2 and +2 respectively.These constant terms is same as well as coefficient of highest degree term, then number of coincident zeroes of their product is (A)1 (B) 2 (C) 3(D) none of these
Degree of non zero constant polynomial is -
Determine degree of hardness in term of ppm of CaCO_3 of 10^(-3) molar MgSO_4 (aq).
S CHAND IIT JEE FOUNDATION-ALGEBRAIC EXPRESSIONS -SELF ASSESSMENT SHEET-17
