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(0.06xx0.06xx0.06-0.05xx0.05xx0.05)/(0.0...

`(0.06xx0.06xx0.06-0.05xx0.05xx0.05)/(0.06xx0.06+0.06xx0.05+0.05xx0.05)` gives

A

0.01

B

0.001

C

0.1

D

0.02

Text Solution

AI Generated Solution

The correct Answer is:
To solve the expression \((0.06 \times 0.06 \times 0.06 - 0.05 \times 0.05 \times 0.05) / (0.06 \times 0.06 + 0.06 \times 0.05 + 0.05 \times 0.05)\), we can use the algebraic identity for the difference of cubes and the sum of cubes. ### Step-by-Step Solution: 1. **Identify a and b**: Let \( a = 0.06 \) and \( b = 0.05 \). 2. **Use the difference of cubes formula**: The difference of cubes can be expressed as: \[ a^3 - b^3 = (a - b)(a^2 + ab + b^2) \] Therefore, we can rewrite the numerator: \[ 0.06^3 - 0.05^3 = (0.06 - 0.05)(0.06^2 + 0.06 \times 0.05 + 0.05^2) \] This simplifies to: \[ 0.01(0.06^2 + 0.06 \times 0.05 + 0.05^2) \] 3. **Calculate the denominator**: The denominator is: \[ 0.06^2 + 0.06 \times 0.05 + 0.05^2 \] This is the same expression we found in the numerator: \[ 0.06^2 + 0.06 \times 0.05 + 0.05^2 \] 4. **Substitute back into the expression**: Now we can substitute back into our original expression: \[ \frac{0.01(0.06^2 + 0.06 \times 0.05 + 0.05^2)}{0.06^2 + 0.06 \times 0.05 + 0.05^2} \] 5. **Simplify the expression**: The \(0.06^2 + 0.06 \times 0.05 + 0.05^2\) terms cancel out: \[ = 0.01 \] ### Final Answer: The value of the expression is \(0.01\).
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