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The volume (in my) of a cube whose diago...

The volume (in my) of a cube whose diagonal is 2.5 metre, is :

A

`(125sqrt(3))/(72)`

B

`625/8`

C

`(125sqrt(2))/(32)`

D

`(125)/8`

Text Solution

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The correct Answer is:
To find the volume of a cube whose diagonal is given as 2.5 meters, we can follow these steps: ### Step-by-Step Solution: 1. **Understand the relationship between the side and the diagonal of a cube**: The diagonal \(d\) of a cube is related to its side length \(a\) by the formula: \[ d = a \sqrt{3} \] 2. **Substitute the given diagonal into the formula**: We know the diagonal \(d = 2.5\) meters, so we can set up the equation: \[ 2.5 = a \sqrt{3} \] 3. **Solve for the side length \(a\)**: To find \(a\), we rearrange the equation: \[ a = \frac{2.5}{\sqrt{3}} \] 4. **Calculate \(a\)**: To simplify \(a\), we can multiply the numerator and denominator by \(\sqrt{3}\): \[ a = \frac{2.5 \sqrt{3}}{3} \] 5. **Find the volume of the cube**: The volume \(V\) of a cube is given by: \[ V = a^3 \] Substituting \(a\) into the volume formula: \[ V = \left(\frac{2.5 \sqrt{3}}{3}\right)^3 \] 6. **Calculate \(V\)**: Expanding the volume: \[ V = \frac{(2.5)^3 (\sqrt{3})^3}{3^3} \] \[ V = \frac{15.625 \cdot 3\sqrt{3}}{27} \] \[ V = \frac{46.875 \sqrt{3}}{27} \] 7. **Final simplification**: We can simplify the fraction: \[ V = \frac{125}{72} \sqrt{3} \text{ cubic meters} \] ### Final Answer: The volume of the cube is: \[ \frac{125 \sqrt{3}}{72} \text{ cubic meters} \]
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