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If (x+ y)^(2) = 21 + z^(2), (y+z)^(2)= 3...

If `(x+ y)^(2) = 21 + z^(2), (y+z)^(2)= 32 + x^(2) and (z+ x)^(2) = 28+ y^(2)`, find `x+ y+ z`=?

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The correct Answer is:
`z = 7`
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