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`P` and `Q` are points on the sides `C A` and `C B` respectively of ` A B C` , right angled at `C` . Prove that `A Q^2+B P^2=A B^2+P Q^2` .

A

`BC^(2)+PQ^(2)`

B

`AB^(2)+PC^(2)`

C

`AB^(2) +PQ^(2)`

D

`BC^(2)+AC^(2)`

Text Solution

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The correct Answer is:
C
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