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If ABC is a right angled triangle at B and M, N are the mid-points of AB and BC, then `4(AN^2+CM^2)` is equal to :

A

`4AC^(2)`

B

`5AC^(2)`

C

`(5)/(4)AC^(2)`

D

`6AC^(2)`

Text Solution

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The correct Answer is:
B
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