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If the median of (x)/(6),(x)/(2),(x)/(4)...

If the median of `(x)/(6),(x)/(2),(x)/(4),(3x)/(5)` and `(7x)/(10)` is 3, then the mean of the given observations is :

A

`2.5`

B

`3.06`

C

`2.16`

D

`2.66`

Text Solution

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The correct Answer is:
To solve the given problem, we need to follow these steps: ### Step 1: Identify the observations The observations given are: 1. \( \frac{x}{6} \) 2. \( \frac{x}{2} \) 3. \( \frac{x}{4} \) 4. \( \frac{3x}{5} \) 5. \( \frac{7x}{10} \) ### Step 2: Arrange the observations in ascending order To find the median, we first need to arrange these observations in ascending order. To do this, we can evaluate the expressions in terms of \( x \): - \( \frac{x}{6} \) = 0.1667x - \( \frac{x}{4} \) = 0.25x - \( \frac{x}{2} \) = 0.5x - \( \frac{3x}{5} \) = 0.6x - \( \frac{7x}{10} \) = 0.7x Arranging these in ascending order gives us: 1. \( \frac{x}{6} \) 2. \( \frac{x}{4} \) 3. \( \frac{x}{2} \) 4. \( \frac{3x}{5} \) 5. \( \frac{7x}{10} \) ### Step 3: Find the median Since there are 5 observations (an odd number), the median is the middle value. The median is the 3rd term in the ordered list: - Median = \( \frac{x}{2} \) According to the problem, the median is given as 3: \[ \frac{x}{2} = 3 \] ### Step 4: Solve for \( x \) To find \( x \), we multiply both sides by 2: \[ x = 6 \] ### Step 5: Calculate the mean of the observations Now, we will calculate the mean of the observations: Mean = \( \frac{\text{Sum of Observations}}{\text{Number of Observations}} \) Substituting the values of \( x \): \[ \text{Sum of Observations} = \frac{6}{6} + \frac{6}{2} + \frac{6}{4} + \frac{3 \cdot 6}{5} + \frac{7 \cdot 6}{10} \] Calculating each term: 1. \( \frac{6}{6} = 1 \) 2. \( \frac{6}{2} = 3 \) 3. \( \frac{6}{4} = 1.5 \) 4. \( \frac{18}{5} = 3.6 \) 5. \( \frac{42}{10} = 4.2 \) Now, summing these values: \[ 1 + 3 + 1.5 + 3.6 + 4.2 = 13.3 \] ### Step 6: Calculate the mean Now, divide the sum by the number of observations (which is 5): \[ \text{Mean} = \frac{13.3}{5} = 2.66 \] ### Final Answer The mean of the given observations is \( 2.66 \). ---
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