Let m be the mid - point and l the upper class limit of a class in a continuous frequency distribution The lowe limit of the class is

Options

A. `2m+l`
B. `2m-l`
C. `m-l`
D. `m-2l`

Answer

To find the lower limit of a class in a continuous frequency distribution when given the midpoint (M) and the upper class limit (L), we can follow these steps:

### Step-by-Step Solution:

1. **Understand the Definitions**:
- Let \( M \) be the midpoint of the class.
- Let \( L \) be the upper class limit.

2. **Use the Midpoint Formula**:
The formula for the midpoint \( M \) of a class is given by:
\[ M = \frac{L + \text{Lower Limit}}{2} \]

3. **Rearrange the Formula**:
To find the lower limit, we can rearrange the formula:
\[ 2M = L + \text{Lower Limit} \]

4. **Isolate the Lower Limit**:
Now, isolate the lower limit in the equation:
\[ \text{Lower Limit} = 2M - L \]

5. **Final Expression**:
Therefore, the lower limit of the class can be expressed as:
\[ \text{Lower Limit} = 2M - L \]

### Conclusion:
The lower limit of the class is given by the formula \( 2M - L \).

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