Find the product by suitable rearrangement:
`125xx40xx8xx25`

Answer

To find the product of the numbers \( 125 \times 40 \times 8 \times 25 \) using suitable rearrangement, we can follow these steps:

### Step 1: Rearrange the Numbers
We can rearrange the numbers to group them in a way that makes multiplication easier. A good arrangement is:
\[ 125 \times 8 \times 25 \times 40 \]

### Step 2: Multiply the First Pair
Now, let's multiply the first two numbers:
\[ 125 \times 8 \]
To do this, we can break it down:
- \( 125 \times 8 = 1000 \)

### Step 3: Multiply the Second Pair
Next, we multiply the next two numbers:
\[ 25 \times 40 \]
Breaking it down:
- \( 25 \times 40 = 1000 \)

### Step 4: Multiply the Results
Now we have two products:
- From Step 2: \( 1000 \)
- From Step 3: \( 1000 \)

Now, we multiply these two results together:
\[ 1000 \times 1000 = 1000000 \]

### Final Answer
Thus, the product of \( 125 \times 40 \times 8 \times 25 \) is:
\[ \boxed{1000000} \]

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