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The sum of - a " and " - a^(2) subtract...

The sum of ` - a " and " - a^(2)` subtracted from `a^(3)` gives

A

`- a ^(6)`

B

`a^(6)`

C

`a - a^(2) + a^(3)`

D

`a + a^(2) + a^(3)`

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The correct Answer is:
To solve the problem step by step, we need to follow the instructions given in the question. The question states that we need to find the result of the sum of `-a` and `-a^2` subtracted from `a^3`. Let's break this down step by step. ### Step 1: Identify the expressions We have: - Expression 1: `-a` - Expression 2: `-a^2` - Expression 3: `a^3` ### Step 2: Find the sum of `-a` and `-a^2` To find the sum of `-a` and `-a^2`, we can write it as: \[ \text{Sum} = -a + (-a^2) = -a - a^2 \] ### Step 3: Subtract the sum from `a^3` Now, we need to subtract the sum we found in Step 2 from `a^3`. This can be expressed mathematically as: \[ a^3 - (-a - a^2) \] ### Step 4: Simplify the expression When we subtract a negative, it is equivalent to adding the positive. Therefore, we can rewrite the expression as: \[ a^3 - (-a - a^2) = a^3 + a + a^2 \] ### Step 5: Rearrange the terms We can rearrange the terms in the expression: \[ a^3 + a + a^2 \] ### Final Result Thus, the final result of the expression is: \[ a^3 + a + a^2 \]
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MTG IIT JEE FOUNDATION-ALGEBRAIC EXPRESSIONS-EXERCISE (MULTIPLE CHOICE QUESTION) (LEVEL - 1)
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  3. The sum of - a " and " - a^(2) subtracted from a^(3) gives

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  5. If the perimeter of a triangle is 8x -7 and two sides are 3x +5 and 2x...

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  11. Take away 9/2+x/2+3/5x^2+7/4x^3\ \ \ from\ \ 7/2-x/3-(x^2)/5dot

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  15. John covers x centimetres in one step. How many centimetres does he ...

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  16. Simplify : 4s^(2)t - 5st^(2) - 7s^(2)t - 3s^(2)t^(2) + 3st^(2) + 3s^(2...

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  17. Simplify : a^(3)b - a^(2)b^(3) +4a^(2)b^(3) - 2a^(3)b^(2) - a^(3)b +...

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  18. Subtract (2a - 3b + 4c) from the sum of (a + 3b - 4c), (4a - b +9c) an...

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  19. If a = 1 and b = (-3), the value of 4a^(3)b^(2) - 3a^(2)b + 4ab^(2) - ...

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  20. From the sum fo 5a^(2)b - 7 ab + 10 " and " -3a^(2)b + 3ab - 4, subtra...

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