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If a = 1 and b = (-3), the value of 4a^(...

If a = 1 and b = (-3), the value of `4a^(3)b^(2) - 3a^(2)b + 4ab^(2) - ab ` is

A

`-84`

B

84

C

`-108`

D

`-72`

Text Solution

AI Generated Solution

The correct Answer is:
To find the value of the expression \(4a^3b^2 - 3a^2b + 4ab^2 - ab\) when \(a = 1\) and \(b = -3\), we will substitute these values into the expression step by step. ### Step-by-Step Solution: 1. **Substitute the values of \(a\) and \(b\)**: \[ 4(1)^3(-3)^2 - 3(1)^2(-3) + 4(1)(-3)^2 - (1)(-3) \] 2. **Calculate \(1^3\) and \((-3)^2\)**: \[ 1^3 = 1 \quad \text{and} \quad (-3)^2 = 9 \] Substitute these values back into the expression: \[ 4(1)(9) - 3(1)(-3) + 4(1)(9) - (1)(-3) \] 3. **Simplify each term**: - The first term: \(4 \cdot 1 \cdot 9 = 36\) - The second term: \(-3 \cdot 1 \cdot -3 = 9\) (note that multiplying two negatives gives a positive) - The third term: \(4 \cdot 1 \cdot 9 = 36\) - The fourth term: \(-1 \cdot -3 = 3\) Now, substitute these results back into the expression: \[ 36 + 9 + 36 + 3 \] 4. **Combine all the terms**: \[ 36 + 9 = 45 \] \[ 45 + 36 = 81 \] \[ 81 + 3 = 84 \] 5. **Final Result**: The value of the expression \(4a^3b^2 - 3a^2b + 4ab^2 - ab\) when \(a = 1\) and \(b = -3\) is \(84\).
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