Find the constant term on subtracting `-17x^(2)+(3x-7)" from "2x^(2)+(3x-4x^2)`.

Answer

To find the constant term when subtracting the expression \(-17x^2 + (3x - 7)\) from \(2x^2 + (3x - 4x^2)\), we can follow these steps:

### Step-by-Step Solution:

1. **Write the expressions clearly**:
We have two expressions:
- Expression A: \(2x^2 + (3x - 4x^2)\)
- Expression B: \(-17x^2 + (3x - 7)\)

2. **Combine like terms in each expression**:
- For Expression A:
\[ 2x^2 - 4x^2 + 3x = (2 - 4)x^2 + 3x = -2x^2 + 3x \]
- For Expression B:
\[ -17x^2 + 3x - 7 \]

3. **Set up the subtraction**:
We need to subtract Expression B from Expression A:
\[ (-2x^2 + 3x) - (-17x^2 + 3x - 7) \]

4. **Distribute the negative sign**:
When we subtract, we change the signs of the terms in Expression B:
\[ -2x^2 + 3x + 17x^2 - 3x + 7 \]

5. **Combine like terms**:
- Combine the \(x^2\) terms:
\[ -2x^2 + 17x^2 = 15x^2 \]
- Combine the \(x\) terms:
\[ 3x - 3x = 0 \]
- The constant term is \(+7\).

6. **Identify the constant term**:
The constant term from the final expression \(15x^2 + 0 + 7\) is \(7\).

### Final Answer:
The constant term is \(7\).