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What is the value of x, if 2^(x+5)= 512?...

What is the value of x, if `2^(x+5)= 512`?

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To solve the equation \(2^{(x+5)} = 512\), we will follow these steps: ### Step 1: Rewrite 512 as a power of 2 First, we need to express 512 as a power of 2. We can do this by repeatedly dividing 512 by 2 until we reach 1. - \(512 \div 2 = 256\) - \(256 \div 2 = 128\) - \(128 \div 2 = 64\) - \(64 \div 2 = 32\) - \(32 \div 2 = 16\) - \(16 \div 2 = 8\) - \(8 \div 2 = 4\) - \(4 \div 2 = 2\) - \(2 \div 2 = 1\) Counting the divisions, we see that we divided by 2 a total of 9 times. Therefore, we can write: \[ 512 = 2^9 \] ### Step 2: Set the exponents equal to each other Now that we have \(512\) expressed as \(2^9\), we can rewrite the original equation: \[ 2^{(x+5)} = 2^9 \] Since the bases are the same, we can set the exponents equal to each other: \[ x + 5 = 9 \] ### Step 3: Solve for x Now, we will solve for \(x\) by isolating it: \[ x = 9 - 5 \] \[ x = 4 \] ### Final Answer Thus, the value of \(x\) is: \[ \boxed{4} \] ---
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