Write answers for the following questions
How many mitotic division takes place for the formation of 1024 cells?

Answer

To determine how many mitotic divisions are required to form 1024 cells, we can follow these steps:

### Step-by-Step Solution:

1. **Understanding Cell Division**:
- Each mitotic division of one cell results in two cells.
- Therefore, after one division, we have 2 cells; after two divisions, we have 4 cells; after three divisions, we have 8 cells; and so on.

2. **Identifying the Pattern**:
- The number of cells formed after 'n' mitotic divisions can be expressed as \(2^n\), where \(n\) is the number of divisions.
- For example:
- 1 division: \(2^1 = 2\) cells
- 2 divisions: \(2^2 = 4\) cells
- 3 divisions: \(2^3 = 8\) cells
- 4 divisions: \(2^4 = 16\) cells
- Continuing this pattern, we see that the number of cells doubles with each division.

3. **Setting Up the Equation**:
- We need to find \(n\) such that \(2^n = 1024\).
- This means we need to express 1024 as a power of 2.

4. **Factorizing 1024**:
- We can factor 1024 by continuously dividing by 2:
- \(1024 ÷ 2 = 512\)
- \(512 ÷ 2 = 256\)
- \(256 ÷ 2 = 128\)
- \(128 ÷ 2 = 64\)
- \(64 ÷ 2 = 32\)
- \(32 ÷ 2 = 16\)
- \(16 ÷ 2 = 8\)
- \(8 ÷ 2 = 4\)
- \(4 ÷ 2 = 2\)
- \(2 ÷ 2 = 1\)

5. **Counting the Divisions**:
- From the factorization, we see that we divided by 2 a total of 10 times before reaching 1.
- Therefore, \(1024 = 2^{10}\).

6. **Conclusion**:
- Since \(2^n = 1024\) and we found \(n = 10\), the number of mitotic divisions required to form 1024 cells is **10**.

### Final Answer:
The number of mitotic divisions required to form 1024 cells is **10**.