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Why n-factor of H(3)PO(4) is equal to on...

Why n-factor of `H_(3)PO_(4)` is equal to one?

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Only one acidic hydrogen is present
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Find the n factor of H_(3) PO_(4) in the following reaction. H_(3) PO_(4) + Ca(OH)_(2) rarr CaHPO_(4) + 2H_(2) O

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The number of oxygen atoms present in 24.5 gm of H_(3)PO_(4) is equal to (P = 31)

What is the basicity of H_(3)PO_(2) acid and why ?

Statement-1 : Both H_(3)PO_(3) and H_(3)PO_(4) have the same number of hydrogen atoms but H_(3)PO_(4) is a tribasic acid and H_(3)PO_(3) is a dibasic acid. Statement-2 : 1 mol of H_(3)PO_(3) is neutralised by 2 mol of NaOH while 1 mol of H_(3)PO_(4) is neutralised by 3 mol of NaOH