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Dissolving 120 g or urea (mol. Wt 60) in...

Dissolving 120 g or urea (mol. Wt 60) in 1000 g of water gave a solution of density 1.15 g/ml. The molarity of solution is

A

1.78 M

B

2.0 M

C

2.05 M

D

2.22 M

Text Solution

Verified by Experts

The correct Answer is:
C
`M=(120xx1000)/(60xx973.9)=2.05`
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CENGAGE CHEMISTRY-EQUIVALENT MASS -MANDATORY EXERCISE Exercise Set III
  1. Normality of 0.1 M H(3)PO(4) solution is

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  2. Calculate molarity of 1.8% (w/w) solution of glucose.

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  3. Dissolving 120 g or urea (mol. Wt 60) in 1000 g of water gave a soluti...

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  4. The molarity of a urea solution in which 0.01 g of urea (NH(2)CONH(2))...

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  5. How many grams of sulphuric acid is to be dissolved to prepare 200 ml ...

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  6. What si the molarity of 0.2 N Na(2)CO(3) solution?

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  7. Calculate the mnormality of 250 ml aqueous solution of H(2)SO(4) havin...

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  8. What si the total number of moles of H(2)SO(4) needed to prepare 5.0 L...

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  9. 10 cm^(3) of 0.1 N monobasic acid requires 15 cm^(3) of sodium hydroge...

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  10. What is the molarity of pure water?

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  11. The volume of water to be added to 100 cm^(3) of 0.5 N H(2)SO(4) to ge...

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  12. The molarity of the solution obtained by dissolving 2.5 g of NaCl in 1...

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  13. How many grams of dibasic acid (mol. Wt 200) should be present in 100 ...

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  14. Which of the following is not true for 0.1 M Na(2)CO(3).

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  15. 480 ml of 1.5 M and 520 ml of 1.2 M solution of same substance mixed t...

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  16. Molarity of 0.2 N H(2)BO(3) is

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  17. One molar solution means 1 mole of solute present in

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  18. The volume of water to be added to 100 ml of N/(2)HCl to prepare 500 c...

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  19. 6.022xx10^(20) molecules of glucose are present in 100 ml of the solut...

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  20. The normality of mixture obtained by mixing 100 ml of 0.2 M H(2)SO(4)+...

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