Concentrated aqueous `H_(2)SO_(4)` is 98% `H_(2)SO_(4)` by mass and has density of 1.84 g `cm^(-3)`. What volume of this acid is required to make 5.0 L of 0.500 M `H_(2)SO_(4)` solution?

Explanation

Volume = `m/(rho)=100/(1.84)=54.35cm^(3)`
Number of moles of `H_(2)SO_(4)=98/(98)=1` mole
Molarity = `1/(54.35)x1000=18.4M`
`M_(1)V_(1)=M_(2)V_(2)`
`18.4xxV_(1)=5xx0.500`
`V_(1)=0.136` L or 136 `cm^(3)`