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The Ew of H(3)PO(4) in the reaction is ...

The Ew of `H_(3)PO_(4)` in the reaction is
`Ca(OH)_(2)+H_(3)PO_(4)rarrCaHPO_(4)+2H_(2)O`
(Ca = 40, P = 31, O = 16)

A

49

B

98

C

32.66

D

147

Text Solution

Verified by Experts

The correct Answer is:
A
Since two H-atoms are replaced
`thereforeEw=(Mw)/(n)=98/(2)=49`
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