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The molality of 1 L solution with x% H(2...

The molality of 1 L solution with x% `H_(2)SO_(4)` is equal to 9. The weight of the solvent present in the solution is 910 g. The value of x is:

A

90

B

80.3

C

40.13

D

9

Text Solution

Verified by Experts

The correct Answer is:
B
`"Molality"=(1000xx"Weight of solute")/(Mwxx"Weight of solvent")`
`9=(1000xxW)/(98xx910)`
`W=802.6gL^(-)`
`=80.26` g per 100 mL
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