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N(2)+3H(2)rarr2NH(3) Molecular weight ...

`N_(2)+3H_(2)rarr2NH_(3)`
Molecular weight of `NH_(3)andN_(2)` are `x_(1)andx_(2)`, respctively. Their equivalent weights are `y_(1)andy_(2)`, respectively. Then `(y_(1)-y_(2))` is

A

`((2x_(1)-x_(2))/(6))`

B

`(x_(1)-x_(2))`

C

`(3x_(1)-x_(2))`

D

`(x_(1)-3x_(2))`

Text Solution

Verified by Experts

The correct Answer is:
A
`N_(2)=2HH_(3)=3H_(2)=6H`
Ew of `N_(2)=x_(2)/(6)=y^(2)`
Ew of `NH_(3)=(2x_(1))/(6)=y_(1)`
`thereforey_(1)-y_(2)=((2x_(1))/(6)-x_(2)/(6))=((2x_(1)-x_(2))/(6))`
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