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If `alpha` and `beta` are the roots of the equation `2x^2-3x + 4=0`, then the equation whose roots are `alpha^2` and `beta^2,` is a. `4x^(2)+7x+16=0` b. `4x^(2)+7x+6=0` c. `4x^(2)+7x+1=0` d. `4x^(2)-7x+16=0`

A

`4x^(2)+7x+16=0`

B

`4x^(2)+7x+6=0`

C

`4x^(2)+7x+1=0`

D

`4x^(2)-7x+16=0`

Text Solution

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The correct Answer is:
A
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Knowledge Check

  • If alpha, beta are the roots of the equation x^2 – 2x + 2 = 0 , then the value of alpha +beta^2 is

    A
    `2`
    B
    `0`
    C
    `1`
    D
    `4`

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