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Solve the equation x^(log(x)(x+3)^(2))=1...

Solve the equation `x^(log_(x)(x+3)^(2))=16`.

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The correct Answer is:
`x epsilon phi`
`x^(log_(x)(x+3)^(2))=16`…….i
Equatioin is defined when
`xgt0, x!=1, x!=-3,`
Then `(x+3)^(2)=4^(2)` [ by property]
`impliesx+3=+-4`
`:.x=1` and `x=-7`
But `x!=1, x!=-7`
i.e. no solution ltbr `:.x epsilon phi`
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