If `veca, vecb and vecc` are non-coplanar vectors, prove that the four points `2veca+3vecb-vecc, veca-2vecb+3vecc, 3veca+4vecb-2vecc and veca-6vecb+ 6 vecc` are coplanar.

What is [vecavecbvecc] when veca,vecb,vecc are coplanar ?

If veca, vecb and vecc are non-coplanar vectors and lamda is a real number, then the vectors veca + 2vecb + 3vecc, lamda vecb + mu vecc and (2lamda -1)vecc are coplanar when

Show that the three points veca-2vecb+3vecc, 2veca+3vecb-4vecc and -7vecb+10vecc are collinear.

If veca, vecb and vecc are any three non-coplanar vectors, then prove that points l_(1)veca+ m_(1)vecb+ n_(1)vecc, l_(2)veca+m_(2)vecb+n_(2)vecc, l_(3)veca+m_(3)vecb+ n_(3)vecc, l_(4)veca + m_(4)vecb+ n_(4)vecc are coplanar if |{:(l_(1),, l_(2),,l_(3),,l_(4)),(m_(1),,m_(2),,m_(3),,m_(4)), (n_1,,n_2,, n_3,,n_4),(1,,1,,1,,1):}|=0

If veca,vecb and vecc are non coplanar and unit vectors such that vecaxx(vecbxxvecc)=(vecb+vecc)/sqrt2 then the angle between veca and vecb is

If veca,vecb,vecc are coplanar then show that veca+vecb, vecb+vecc and vecc+veca are also coplanar.

prove that : [veca+vecb,vecb+vecc,vecc+veca]=2[veca,vecb,vecc]

For any three vectors veca,vecb,vecc show that veca-vecb,vecb-vecc,vecc-veca are coplanar.

If veca, vecb, vecc are non coplanar vectors and lamda is a real number, then [(lamda(veca+vecb), lamda^(2)vecb, lamdavecc)]=[(veca, vecb+vecc,vecb)] for