Home
Class 12
MATHS
The equation of the lines x+y+z-1=0and4x...

The equation of the lines `x+y+z-1=0and4x+y-2z+2=0` written in the symmetrical form is

A

`(x+1)/(1)=(y-2)/(-2)=(z-0)/(1)`

B

`(x)/(1)=(y)/(-2)=(z-1)/(1)`

C

`((x+1)/(2))/(1)=(y-1)/(-2)=((z-1)/(2))/(1)`

D

`(x-1)/(2)=(y+2)/(-1)=(z-2)/(2)`

Text Solution

Verified by Experts

The correct Answer is:
(a, b, c, d)
Promotional Banner

Topper's Solved these Questions

  • THREE DIMENSIONAL COORDINATE SYSTEM

    ARIHANT MATHS|Exercise JEE Type Solved Examples : Matching Type Questions|5 Videos
  • THREE DIMENSIONAL COORDINATE SYSTEM

    ARIHANT MATHS|Exercise Exercise For Session 1|12 Videos
  • THEORY OF EQUATIONS

    ARIHANT MATHS|Exercise Exercise (Questions Asked In Previous 13 Years Exam)|35 Videos
  • TRIGONOMETRIC EQUATIONS AND INEQUATIONS

    ARIHANT MATHS|Exercise Exercise (Questions Asked In Previous 13 Years Exam)|12 Videos

Similar Questions

Explore conceptually related problems

Reduce the equation of line x-y+2z=5a d n3x+y+z=6 in symmetrical form. Or Find the line of intersection of planes x-y+2z=5a n d3x+y+z=6.

Given the equation of the line 3x-y+z+1=0 and 5x+y+3z=0 . Then,which of the following is correct?

Find the equation of the plane through the intersection of the planes : 3x - y + 2z - 4 = 0 and x + y + z - 2 = 0 and the point (2, 2, 1 ).

Find the equation of the plane through the line of intersection of the planes: x+3y-z+1=0 and x+y-2z+3=0 and perpendicular to the plane 3x-y-2z-4=0

Let the equation of the plane containing line x-y-z-4=0=x+y+2z-4 and parallel to the line of intersection of the planes 2x+3y+z=1 and x+3y+2z=2 be x+Ay+Bz+C=0 . Then the values of |A+B+C-4| is …..

Parametric equations of a line are x=-1+2t, y=3-4t and z=2+t. find the equations of the line in the symmetrical form.

The equation of the line passing through (1, 1, 1) and perpendicular to the line of intersection of the planes x+2y-4z=0 and 2x-y+2z=0 is