Home
Class 12
MATHS
Consider the equation of line AB is (x)/...

Consider the equation of line AB is `(x)/(2)=(y)/(-3)=(z)/(6)`. Through a point P(1, 2, 5) line PN is drawn perendicular to AB and line PQ is drawn parallel to the plane `3x+4y+5z=0` to meet AB is Q. Then,

A

coordinate of N are `((52)/(49), -(78)/(49), (156)/(49))`

B

the coordinate of Q are `(3, -(9)/(2), 9)`

C

the equation of PN is `(x-1)/(3)=(y-2)/(-176)=(z-5)/(-89)`

D

coordinate of N are `((156)/(49), (52)/(49), -(78)/(49))`

Text Solution

Verified by Experts

The correct Answer is:
(a, b, c)
Promotional Banner

Topper's Solved these Questions

  • THREE DIMENSIONAL COORDINATE SYSTEM

    ARIHANT MATHS|Exercise JEE Type Solved Examples : Matching Type Questions|5 Videos
  • THREE DIMENSIONAL COORDINATE SYSTEM

    ARIHANT MATHS|Exercise Exercise For Session 1|12 Videos
  • THEORY OF EQUATIONS

    ARIHANT MATHS|Exercise Exercise (Questions Asked In Previous 13 Years Exam)|35 Videos
  • TRIGONOMETRIC EQUATIONS AND INEQUATIONS

    ARIHANT MATHS|Exercise Exercise (Questions Asked In Previous 13 Years Exam)|12 Videos

Similar Questions

Explore conceptually related problems

The equation of line is (2x-5)/4=(y+4)/3=(6-z)/6 then the d.c.'s ofline parallel of this line are :

Find the equation of a line through the point (-2,3) and parallel to the line 3x-4y+2=0.

Find the equation of the plane through the points (2, -3, 1) and (5, 2, -1) and perpendicular to the plane x -4y + 5z + 2 = 0.

Write the equation of a line, parallel to the line (x-2)/-3=(y+3)/2=(z+3)/6 and passing through the point (1,2,3).

Find the direction cosine of a line parallel to the line (2x-5)/(4)=(y+4)/(3)=(6-z)/(6)

Find equation of the line parallel to the line 3x-4y+ 2=0 and passing through the point (-2, 3).

The Cartesian equation of a line is (x+3)/2 = (y-5)/4 = (z+6)/2 . Find the vector equation for the line.