Let the line (x-2)/(3)=(y-1)/(-5)=(z+2)/...

Let the line `(x-2)/(3)=(y-1)/(-5)=(z+2)/(2)` lies in the plane `x+3y-alphaz+beta=0`. Then, `(alpha, beta)` equals

`(6, -17)`

`(-6, 7)`

`(5, -15)`

`(-5, 15)`

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The correct Answer is:

(b)

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