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`underset(nrarroo)limunderset(r=1)overset(n)Sigma(r)/(1xx3xx5xx7xx9xx...xx(2r+1))` is equal to

A

`1/2[1-1/(1xx3xx5....(2n+1))]`

B

`1/4[1-1/(1xx3xx5....(2n-1))]`

C

`1/4[1+1/(1xx3xx5....(2n-1))]`

D

None of these

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