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If Cr=^nCr then (C1)/2-(C2)/3+(C3)/4-...

If `C_r=^nC_r` then `(C_1)/2-(C_2)/3+(C_3)/4-...........-(C_100)/101` is equal to

A

`C_(1)`

B

`C_(2)`

C

`C_(3)`

D

`C_(4)`

Text Solution

Verified by Experts

The correct Answer is:
b
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