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The sum sum(r=0)^n (r+1) (Cr)^2 is equal...

The sum `sum_(r=0)^n (r+1) (C_r)^2` is equal to :

A

`((n+2)(2n -1)!)/(n!(n-1)!)`

B

`((n+2)(2n+1)!)/(n!(n-1)!)`

C

`((n+2)(2n+1)!)/(n!(n+1)!)`

D

`((n+2)(2n-1)!)/(n!(n+1)!)`

Text Solution

Verified by Experts

The correct Answer is:
a
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