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sum(r=1)^(n) {sum(r1=0)^(r-1) ""^(n)C(r...

` sum_(r=1)^(n) {sum_(r1=0)^(r-1) ""^(n)C_(r) ""^(r)C_(r_(1)) 2^(r1)}` is equal to

A

` 4^(n) - 3^(n) + 1`

B

`4^(n) - 3^(n) -1`

C

`4^(n) - 3^(n) + 2`

D

`4^(n) - 3^(n)`

Text Solution

Verified by Experts

The correct Answer is:
d
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