A ray of light is sent along the line `2x-3y=5.` After refracting across the line `x+y=1` it enters the opposite side after torning by `15^0` away from the line `x+y=1` . Find the equation of the line along which the refracted ray travels.

If a ray travelling the line x = 1 gets reflected the line x+y=1 then the equation of the line along which the reflected ray travels is

A ray of light travelling along the line x+y=1 is incident on the X - axis and after refraction the other side of the X - axis by turning pi//6 by turning away from the X - axis .The equation of the line along which the refracted ray travels is

A ray of light is sent along the line x-2y-3=0 upon reaching the line 3x-2y+7=0, the ray is reflected from it. Find the equation of the line containing the reflected ray.

Find the slop of line . The Equation of line is 2x-3y=2

Find the slop of line . The Equation of line is 2x-5y=4

A ray of light travels along a line y=4 and strikes the surface of curves y^2=4(x+y)dot Then the equations of the line along which of reflected ray travels is x=0 (b) x=2 (c) x+y (d) 2x+y=4

The Cartesian equation of a line is (x-3)/2=(y+1)/(-2)=(z-3)/5 . Find the vector equation of the line.

The equation of the line AB is y = x . If A and B lie on the same side of the line mirror 2x-y = 1 , then the equation of the image of AB is

A ray of light is coming along the line y=b from the positive direction of x-axis and striks a concave mirror whose intersection with x-plane is a parabola y^2 = 4ax . Find the equation of the reflected ray and show that it passes through the focus of the parabola. Both a and b are positive.

If a ray of light incident along the line 3x+(5-4sqrt2)y=15 gets reflected from the hyperbola (x^(2))/(16)-(y^(2))/(9)=1, then its reflected ray goes along the line