Home
Class 12
MATHS
Through the point P(alpha,beta) , where ...

Through the point `P(alpha,beta)` , where `alphabeta>0,` the straight line `x/a+y/b=1` is drawn so as to form a triangle of area `S` with the axes. If `a b >0,` then the least value of `S` is

A

`alpha beta`

B

`2 alpha beta`

C

`4alpha beta`

D

`8 alpha beta`

Text Solution

Verified by Experts

Promotional Banner

Topper's Solved these Questions

  • THE STRAIGHT LINES

    ARIHANT MATHS|Exercise Example|3 Videos

  • THE STRAIGHT LINES

    ARIHANT MATHS|Exercise JEE Tyep Solved Examples : (Paragraph Based Questions)|13 Videos

  • SETS, RELATIONS AND FUNCTIONS

    ARIHANT MATHS|Exercise Exercise (Questions Asked In Previous 13 Years Exam)|12 Videos

  • THEORY OF EQUATIONS

    ARIHANT MATHS|Exercise Exercise (Questions Asked In Previous 13 Years Exam)|35 Videos

Similar Questions

Explore conceptually related problems

The straight lines x+y=0, 3x+y=4 and x+3y=4 form a triangle which is

If a pair of perpendicular straight lines drawn through the origin forms an isosceles triangle with the line 2x+3y=6 , then area of the triangle so formed is

A variable straight line is drawn through the point of intersection of the straight lines x/a+y/b=1 and x/b+y/a=1 and meets the coordinate axes at A and Bdot Show that the locus of the midpoint of A B is the curve 2x y(a+b)=a b(x+y)

Find the equation of the straight line through the point P(a,b) parallel to the line x/a+y/b = 1 also find the intercepts made by it on the axes .

If non-zero numbers a,b,c are in H.P., then the straight line x/a+ y/b+1/c=0 always passes through a fixed point. That point is :

If a and b ( != 0) are roots of x^(2) +ax + b = 0 , then the least value of x^(2) +ax + b ( x in R) is :

Let P be a variable point on the ellipse x^(2)/25 + y^(2)/16 = 1 with foci at S and S'. If A be the area of triangle PSS' then the maximum value of A, is

Find the area of the triangle formed by the lines y-x=0, x+y=0 and x-k=0.

The straight line through the point of intersection of ax + by+c=0 and a'x+b'y+c'= 0 are parallel to the y-axis has the equation

Find the direction in which a straight line must be drawn through the point (1,2) so that its point of intersection with the line x+y=4 may be at a distance 1/3 sqrt(6) from this point