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Line x/a+y/b=1 cuts the coordinate axes ...

Line `x/a+y/b=1` cuts the coordinate axes at `A(a ,0)a n dB(0,b)` and the line `x/a^(prime)+y/b^(prime)=-1` at `A (-a ,)` and `B^(prime)(0,-b^(prime))dot` If the points `A ,B ,A^(prime),B '` are concyclic, then the orthocentre of triangle `A B A '` is `(0,0)` (b) `(0,b^(prime))` `(0,(a a^(prime))/b)` (d) `(0,(b b^(prime))/a)`

A

`(0,0)`

B

`(0,b)`

C

`(0,(-aa)/b)`

D

`(0,("bb"')/a)`

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