Home
Class 12
MATHS
In a triangle ABC , if the equation of s...

In a triangle ABC , if the equation of sides AB,BC and CA are `2x- y + 4 = 0 , x - 2y - 1 = 0 and x + 3y - 3 = 0 ` respectively ,Tangent of internal angle A
is equal to

A

`x-y-1 =0`

B

`x-y+1=0`

C

`x+y-5=0`

D

`x+y+5=0`

Text Solution

Verified by Experts

The correct Answer is:
D
Promotional Banner

Topper's Solved these Questions

  • THE STRAIGHT LINES

    ARIHANT MATHS|Exercise The Straight Lines Exercise 3 : (Paragraph Based Questions)|3 Videos

  • THE STRAIGHT LINES

    ARIHANT MATHS|Exercise Exercise (Single Integer Answer Type Questions)|10 Videos

  • THE STRAIGHT LINES

    ARIHANT MATHS|Exercise Exercise (More Than One Correct Option Type Questions)|15 Videos

  • SETS, RELATIONS AND FUNCTIONS

    ARIHANT MATHS|Exercise Exercise (Questions Asked In Previous 13 Years Exam)|12 Videos

  • THEORY OF EQUATIONS

    ARIHANT MATHS|Exercise Exercise (Questions Asked In Previous 13 Years Exam)|35 Videos

Similar Questions

Explore conceptually related problems

Show that the lines 2x + 3y - 8 = 0 , x - 5y + 9 = 0 and 3x + 4y - 11 = 0 are concurrent.

In triangle ABC, the equation of the right bisectors of the sides AB and AC are x+y=0 and y-x=0. respectively. If A-=(5,7) the find the equation of side BC.

If the equations of three sides of a triangle are x+y=1, 3x + 5y = 2 and x - y = 0 then the orthocentre of the triangle lies on the line/lines

The three sides AB, BC, CA of a triangle are 5x - 3y +2 = 0,x-3y-2=0 and x+y-6=0 respectively. Find equation of the altitude through the vertex A.

Find the equations of the bisectors of the angles formed by the lines : 3x- 4y + 12 = 0 and 4x + 3y + 2=0.

The two curves x^3 - 3x y^2 + 2 = 0 and 3x^2y - y^3 - 2 = 0 intersect at an angle of

Statement 1: The internal angle bisector of angle C of a triangle A B C with sides A B ,A C , and B C as y=0,3x+2y=0, and 2x+3y+6=0 , respectively, is 5x+5y+6=0 Statement 2: The image of point A with respect to 5x+5y+6=0 lies on the side B C of the triangle.

In a triangle, ABC, the equation of the perpendicular bisector of AC is 3x - 2y + 8 = 0 . If the coordinates of the points A and B are (1, -1) & (3, 1) respectively, then the equation of the line BC will be

The equation of the sides of a triangle are x+2y+1=0, 2x+y+2=0 and px+qy+1=0 and area of triangle is Delta .

Find graphically the vertices of the triangle whose sides have the equations y = x, y = 0 and 2x + 3y = 10 .