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P is any point on the x-a=0. If A=(a,0)a...

P is any point on the `x-a=0`. If `A=(a,0)`and PQ , the bisector of `angleOPA` meets the x-axis in Q prove that the locus of the foot of prependicular from Q on OP is `(x-a)^2(x^2+y^2)=a^2y^2`

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