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If H=(x^(2))/(a^(2))-(y^(2))/(b^(2))-1=0...

If `H=(x^(2))/(a^(2))-(y^(2))/(b^(2))-1=0, C=(x^(2))/(a^(2))-(y^(2))/(b^(2))+1=0` and `A=(x^(2))/(a^(2))-(y^(2))/(b^(2))=0` then H, A and C are in

A

(a) AP

B

(b) GP

C

(c) HP

D

(d) AGP

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The correct Answer is:
A
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ARIHANT MATHS-HYPERBOLA-Exercise For Session 3
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