Home
Class 12
MATHS
ABC is a triangle such that angleABC=2an...

ABC is a triangle such that `angleABC=2angleBAC`. If AB is fixed and locus of C is a hyperbola, then the eccentricity of the hyperbola is

Text Solution

Verified by Experts

The correct Answer is:
`(2)`
Promotional Banner

Topper's Solved these Questions

  • HYPERBOLA

    ARIHANT MATHS|Exercise Hyperbola Exercise 8 : Matching Type Questions|3 Videos

  • HYPERBOLA

    ARIHANT MATHS|Exercise Exercise (Statement I And Ii Type Questions)|8 Videos

  • HYPERBOLA

    ARIHANT MATHS|Exercise Exercise (Passage Based Questions)|15 Videos

  • GRAPHICAL TRANSFORMATIONS

    ARIHANT MATHS|Exercise Exercise (Questions Asked In Previous 13 Years Exam)|10 Videos

  • INDEFINITE INTEGRAL

    ARIHANT MATHS|Exercise Exercise (Questions Asked In Previous 13 Years Exam)|8 Videos

Similar Questions

Explore conceptually related problems

sqrt 2009/3 (x^2-y^2)=1 , then eccentricity of the hyperbola is :

The eccentricity of the hyperbola 4x^(2)-9y^(2)=36 is :

In fig., ABC is a triangle in which angleABC .

Let the tangent at a point P on the ellipse meet the major axis at B and the ordinate from it meet the major axis at A. If Q is a point on the AP such that AQ=AB , prove that the locus of Q is a hyperbola. Find the asymptotes of this hyperbola.

Let A=(-3, 4) and B=(2, -1) be two fixed points. A point C moves such that tan((1)/(2)angleABC):tan((1)/(2)angleBAC)=3:1 Thus, locus of C is a hyperbola, distance between whose foci is

Statement-I A hyperbola whose asymptotes include (pi)/(3) is said to be equilateral hyperbola. Statement-II The eccentricity of an equilateral hyperbola is sqrt(2).

The tangent at a point P on the hyperbola (x^2)/(a^2)-(y^2)/(b^2)=1 passes through the point (0,-b) and the normal at P passes through the point (2asqrt(2),0) . Then the eccentricity of the hyperbola is

The normal at P to a hyperbola of eccentricity (3)/(2sqrt(2)) intersects the transverse and conjugate axes at M and N respectively. The locus of mid-point of MN is a hyperbola, then its eccentricity.

The equation of a hyperbola conjugate to the hyperbola x^(2)+3xy+2y^(2)+2x+3y=0 is