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An ellipse intersects the hyperbola 2x^2...

An ellipse intersects the hyperbola `2x^2-2y =1` orthogonally. The eccentricity of the ellipse is reciprocal to that of the hyperbola. If the axes of the ellipse are along the coordinate axes, then (a) the foci of ellipse are `(+-1, 0)` (b) equation of ellipse is `x^2+ 2y^2 =2` (c) the foci of ellipse are `(t 2, 0)` (d) equation of ellipse is `(x^2 2y)`

A

equation of ellipse `x^(2)+2y^(2)=2`

B

the foci of the ellipse are `(pm1,0)`

C

equation of ellipse is `x^(2)+2y^(2)=4`

D

the foci of ellipse are `(pmsqrt(2), 0)`

Text Solution

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The correct Answer is:
A, B
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