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The circle x^2+y^2-8x = 0 and hyperbola ...

The circle `x^2+y^2-8x = 0` and hyperbola `x^2 /9 - y^2 /4=1` intersect at the points A and B. Then the equation of the circle with AB as its diameter is

A

`x^(2)+y^(2)-12x+24=0`

B

`x^(2)+y^(2)+12x+24=0`

C

`x^(2)+y^(2)+24x-12=0`

D

`x^(2)+y^(2)-24x-12=0`

Text Solution

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The correct Answer is:
A
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