Home
Class 14
MATHS
HCF of 6/5,3/25,9/15,12/5...

HCF of `6/5,3/25,9/15,12/5`

A

`12/25`

B

`12/5`

C

`3/55`

D

`1/25`

Text Solution

AI Generated Solution

The correct Answer is:
To find the HCF (Highest Common Factor) of the fractions \( \frac{6}{5}, \frac{3}{25}, \frac{9}{15}, \frac{12}{5} \), we can follow these steps: ### Step 1: Identify the numerators and denominators The fractions are: - Numerators: 6, 3, 9, 12 - Denominators: 5, 25, 15, 5 ### Step 2: Find the HCF of the numerators To find the HCF of the numerators (6, 3, 9, 12): - The factors of 6 are: 1, 2, 3, 6 - The factors of 3 are: 1, 3 - The factors of 9 are: 1, 3, 9 - The factors of 12 are: 1, 2, 3, 4, 6, 12 The common factors are: 1, 3. The highest common factor is 3. ### Step 3: Find the LCM of the denominators To find the LCM of the denominators (5, 25, 15, 5): - The prime factorization of 5 is \( 5^1 \) - The prime factorization of 25 is \( 5^2 \) - The prime factorization of 15 is \( 3^1 \times 5^1 \) The LCM is found by taking the highest power of each prime: - For 5: \( 5^2 \) - For 3: \( 3^1 \) Thus, the LCM is \( 5^2 \times 3^1 = 25 \times 3 = 75 \). ### Step 4: Write the HCF of the fractions Now that we have the HCF of the numerators (3) and the LCM of the denominators (75), we can write the HCF of the fractions: \[ \text{HCF} = \frac{\text{HCF of numerators}}{\text{LCM of denominators}} = \frac{3}{75} \] ### Step 5: Simplify the fraction To simplify \( \frac{3}{75} \): \[ \frac{3 \div 3}{75 \div 3} = \frac{1}{25} \] ### Final Answer The HCF of the fractions \( \frac{6}{5}, \frac{3}{25}, \frac{9}{15}, \frac{12}{5} \) is \( \frac{1}{25} \). ---
Promotional Banner

Topper's Solved these Questions

Similar Questions

Explore conceptually related problems

What is the HCF of 4/5 , 6/8, 8/25 ?

Find HCF of (6)/(4),(4)/(15),(2)/(5)

(a) Find the HCF of (2)/(5),(12)/(5) and (3)/(4)

HCF of (4)/(5),(5)/(6),(9)/(10) is

Find the HCF of 4/5 and 7/(15)