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A current of 0.1 A flows through a 25 Om...

A current of 0.1 A flows through a 25 `Omega` resistor represented by the circuit diagram. The current in the 80 `Omega` resistor is

A

0.1 A

B

0.2 A

C

0.3 A

D

0.4 A

Text Solution

Verified by Experts

The correct Answer is:
C

`0.1 xx ( 25 +(20xx60)/(20+60)) = i_2 xx 20`
`I_2 = 0.2 A`
Hence , `i` through `80 Omega`
0.1 + 0.2 = 0.3 A
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