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0.102 g of an organic compound X was oxi...

0.102 g of an organic compound X was oxidized with fuming nitric acid. The resulting solution, after reaction with an excess of aqueous `BaCl_2` produced 0.233 g of `BaSO_4` as a precipitate , compound X is likely to be :
[Given : Atomic wt. of Ba = 137]

A

B

C

D

Text Solution

Verified by Experts

The correct Answer is:
D
0.233 gm BaSO4 has 1 millimole BaSO4 and hence has 1millimole S
`therefore` organic compound (X) also has 1millimole S
% of S in 0.102 gm of organic compound (X)
`=(0.032)/(0.012)x100=31.37%`

102 gm of this organic compound has 32 gm S
This has same % of S.
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