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Sodium borohydride upon treatment with i...

Sodium borohydride upon treatment with iodine produces a Lewis acid (X), which on heating with ammonia produces a cyclic compoud (Y) and a colorless gas (Z). X, Y and Z are:

A

`X = BH_3 , Y = BH_3. NH_3 , Z = N_2 `

B

`X = B_2 H_6 , Y = B_3 N_3 H_6 , Z = H_2`

C

` X = B_2 H_6, Y = B_6 H_6, Z = H_2 `

D

` X = B_2 H_6 , Y = B_3 N_3 H_6, Z = N_2 `

Text Solution

Verified by Experts

The correct Answer is:
B
` 2Na[BH_4]+I_2 to B_2 H_6 (X ) + 2Nal +H_2 `
` 3B_2 H_6 +6NH_3 overset(Delta )to 2B_3 N_3 H_6 (Y ) + 12 H_2 (Z)`
` X = B_2 H_6`
` Y = B_3 N_3 H_6 `
` Z= 12 H_2`
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