Home
Class 12
MATHS
Verify Lagrange's Mean Value Theorem for...

Verify Lagrange's Mean Value Theorem for the function : `f(x) = x (x - 1) (x - 2) (x - 3)` in the interval `[0,4]`

Promotional Banner

Topper's Solved these Questions

  • CONTINUITY AND DIFFERENTIABILITY

    BETTER CHOICE PUBLICATION|Exercise SOLVED EXAMPLES (Long Answer Type Questions)(Section XII)|4 Videos
  • CONTINUITY AND DIFFERENTIABILITY

    BETTER CHOICE PUBLICATION|Exercise ASSIGNMENT (MOST IMPORTANT QUESTIONS FOR PRACTICE)(SECTION I)(MULTIPLE CHOICE QUESTIONS) |8 Videos
  • CONTINUITY AND DIFFERENTIABILITY

    BETTER CHOICE PUBLICATION|Exercise SOLVED EXAMPLES (Short Answer Type Questions)(Section X)|13 Videos
  • APPLICATIONS OF DERIVATIVES

    BETTER CHOICE PUBLICATION|Exercise PREVIOUS YEAR BOARD.S QUESTIONS FOR PRACTICE |73 Videos
  • DETERMINANTS

    BETTER CHOICE PUBLICATION|Exercise ASSIGNMENT (PREVIOUS YEAR.S BOARD QUESTIONS FOR PRACTICE )|45 Videos

Similar Questions

Explore conceptually related problems

Verify Lagrange's Mean Value Theorem for the function : f(x) = x (x - 1) (x - 2) in the interval [0,1/2]

Verify Lagrange's mean value theorem for the function f(x) = x (x - 3 ) (x - 6)(x-9) in the interval [3,5] .

Verify Lagrange's mean value theorem for the function f(x) = x (x - l ) (x - 2) in the interval [0,1/2] .

Verify Lagrange's mean value theorem for the following functions f(x) = (x - 1)^(2//3) in the interval [1,2]

Verify Lagrange's mean value theorem for the following functions f(x) = x^3 - 2x^2 - x + 3 in the interval [0,1]

Verify Lagrange's Mean Value Theorem for the function f defined by f(x) = x^3 + x^2 - 6x in the interval [-1,4]

Verify Lagrange's Mean value Theorem (LMV.) for the function f(x) = x(2-x) in [0,1]

Verify Lagrange's mean value theorem for the following functions f(x) = x^3 - 5x^2 - 3x in the interval [1,3]

Verify the Lagrange's Mean Value Theorem for the functions: f(x) = alpha on [a,b]

Verify Lagrange's mean value theorem for the following functions f(x) = x(x - 1)^2 in the interval [0,1]